10x^2-10.5x=0

Solution for 10x^2-10.5x=0 equation:

10x^2-10.5x=0

a = 10; b = -10.5; c = 0;
Δ = b2-4ac
Δ = -10.52-4·10·0
Δ = 110.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10.5)-\sqrt{110.25}}{2*10}=\frac{10.5-\sqrt{110.25}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10.5)+\sqrt{110.25}}{2*10}=\frac{10.5+\sqrt{110.25}}{20}
$